A particle moving in a straight line covers half of the distance with a speed of 13ms^2. The other half is covered in two equal time intervals with a speed of 14.5ms^2and 17.5ms^2respectively. The average speed of the particle during its motion is Search Results Web results
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Half distance ===> 13m/s
Half distance ===> In two equal time periods one with 14.5m/s and another 17.5m/s.
Let total distance be 2x.
x with 13m/s. And remaining x with 14.5m/s and 17.5m/s.
In the second half its saying equal time period.
Half distance ===> x
Average speed = Total distance / Total time
In second half:
Total distance in second half = x
x = 14.5 x t + 17.5 x t
x = 32t
x/32 = t
Total time in second half.
In First Half:
Distance/ Speed = Time
x/13m/s = Time
Total distance ===> 2x
Total time ===> x/32 + x/13 = (13x+32x)/416 = 45x/416
2x/45x/416 = Total distance/Total time
Total distance/Total time = 18.48 m/s
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