Question

a particle moving in a straight line covers half the distance with a speed of 3m/s and the other half of the distance is covered in two equal time intervals with speed 4.5m/s and 7.5m/s respectively. then the average speed of particle during this motion is​

Answer 1

Explanation:

let total distance of path is S ...

for first half , time taken if t

speed = distance/time

3 = S/2t

t = S/6 .............1

for second half , time taken is T ...

for first T/2 it moves with 4.5

speed = distance/time

4.5 = 2x/T

x = 4.5T/2 ...........2

for second T/2 it moves with 7.5

7.5 = 2y/T

y = 7.5T/2 ..........3

we have , x+y = S/2so

(7.5+4.5)T = S/2

T = S/24 ...............4

total time taken during its motion is T+t

Ttotal = T+t = S/24+S/6 = 5S/24

total distance = S

average speed = total distance/total time = S/5S/24 = 24/5 = 4.8m/s

let the distanc covered with speed 3m/s be x.mts

time taken is x/3sec.

ii)second half(x mts)

time taken to travel second half will be 18x/11.25 sec

avg. speed=total distanc /totaltime

avg.speed=1.9m/s

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Answer 2

Answer:

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nice question

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