Question

A particle moving in a straight line covers half the distance with speed 3m/s and the other half with 6m/s speed. What's the average speed of the particle?

Answer 1

Answer:

4m/s

Explanation:

Let the total distance travelled be d

$v = \frac{d}{t}$

we need to find t, that is total time taken.

The particle travels first half distance d/2 at 3m/s and the other half at 6m/s

$t = \frac{d}{s}$

total time taken during first half distance is

d/(6)s and during the second half, time taken is. d/(12)

total time thus is,

$t = \frac{d}{ 6} + \frac{d}{12} = \frac{d}{4} s$

$v = \frac{d}{t} = \frac{d}{ \frac{d}{4} } = 4m{s}^{ - 1}$

Answer 2

Particle cover the half distance = 3m/s

Particle cover other half distance = 6m/s. Total time = 1/2 +1/2. = 1+1 /2 = 2/2 = 1 min. Formula of average speed = total distance travelled/total time taken.

= 3 + 6 / 1 min = 9 m/ s .