A particle moving in a straight line covers half the total distance with a speed of 3ms^-1 and half of is covered with speed of 2ms^-1 and the rest with a speed of 3ms^-1. Find the average speed of the particle during this motion.
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t1=32S=6S
2S=4.5×t2+7.5t3⇒12t2=2S
We have t2=t3
Total time t=t1+t2+t3=6S+24S+24S=4S
Average of tS=4SS=4m/s
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Answer:
average speed is = 4m/s....
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