A particle moving in a straight line forwards half of the total distance with speed of 3 m / s the other half of the distance is covered in 2 equal time intervals with speed of 4. 5 M / S and 7.5 M / s the average speed of the particle during this motion
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first half distance covered with 3.5 m/s
second half distance covered by 2 equal time interval speed of 4.5 m/s and 7.5 m/s
let be assume the equal time interval of second half 10
so the 4.5*10=45m
and 7.5*10=75m
we take 10 s in both condition because time is same in both condition
so the total of second half distance = 120m
so first half also be a 120 m
total distance = 240
time taken to covered first half = 120/3.5=34.285714
average speed=total distance divide by total time
= 240/54.285714= 4.4210 m/s
distance = speed * time
time = distance/speed
second half distance covered by 2 equal time interval speed of 4.5 m/s and 7.5 m/s
let be assume the equal time interval of second half 10
so the 4.5*10=45m
and 7.5*10=75m
we take 10 s in both condition because time is same in both condition
so the total of second half distance = 120m
so first half also be a 120 m
total distance = 240
time taken to covered first half = 120/3.5=34.285714
average speed=total distance divide by total time
= 240/54.285714= 4.4210 m/s
distance = speed * time
time = distance/speed
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