A particle moving in a straight line forwards half of the total distance with speed of 3 m / s the other half of the distance is covered in 2 equal time intervals with speed of 4. 5 M / S and 7.5 M / s the average speed of the particle during this motion
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Avg speed = (4.5 + 7.5 )/ 2
= 12 / 2
= 6 m /s
This the avg speed of the one half ........
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Now the avg speed of the entire journey
= (12 + 3 ) / 3
= 15 / 3
= 5 m/s
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Jiya22
Secondary SchoolPhysics 13+7 pts
A particles moving in a straight line covers half of the total distance with a speed of 3 m/s. The other half of the distance is covered in two equal time intervals with speeds of 4.5 m/s and 7.5 m/s. The average speed of the particle during this motion is (a) 4 m/s (b) 5 m/s (c) 5.5 m/s (d) 4.8 m/s
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rahulsirtm
Rahulsirtm Ambitious
5.5 is the average speed
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Jiya22
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Jiya22
Jiya22 Ambitious
Answer: a)4m/s is the correct answer
Explanation:
Let the distance covered be 2d.
Time taken to cover d
(T) = d/3 ....(since, t=d/s)
Now other half is covered in equal intervals of time.. let them be t.
d = 4.5t+7.5t
d=12t
t=d/12
Average Speed = Total distance/Total time
= 2d/( d/3+d/12+d/12)
= 2d/3d/6
= 4m/s