A particle moving in an initial velocity of 5m/s is subjected to a uniform acceleration of -2.5m/s. Find the displacement in the next 4 sec
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Displacement is given by the equation
s=ut + 1/2at^2
u is initial velocity
a acceleration
t time
s displacement
By substituting the given values we get
s=5*4+(1/2*[-2.5]*(4)^2
=20-20
=0
That means there no displacement
s=ut + 1/2at^2
u is initial velocity
a acceleration
t time
s displacement
By substituting the given values we get
s=5*4+(1/2*[-2.5]*(4)^2
=20-20
=0
That means there no displacement
Answered by
0
Answer:
Explanation:
U is 5
A is 2.5
T is 4
S = ut+½at²
S = 5×4+½×2.5(4)²
S = 20 + 20
S = 40
Here we can take displacement as distance that's why here I took displacement as *s*
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