A particle moving on x-axis has potential energy U = 2 - 20x + 5x^2 J along x-axis.
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"A particle moving on x-axis has potential energy U = 2 - 20x + 5x^2 J along x-axis.
In equilibrium the maximum X coordinate can be calculated as
U= 2-20X + 5X^2 as
F = dU / d x = 20-10x
20=10x
X=2
F = 0 at x = 2, i.e., x = 2 is the equilibrium position.
As particle is released from x = -3 then the amplitude value is 5 m.
Thus, maximum x coordinate can be calculates by adding 2 terms
2m+5m = 7m
"
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