A particle moving rectilinearly with constant acceleration is having initial velocity of 10 M per second after sometime velocity becomes 30 metre per second find the velocity of particle at the midpoint of its path
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Let the total distance be 2x
Therefore distance up to mid point is equal to x.
Let the velocity at midpoint be v
And acceleration be a.
From equations of motion :
v² = 10² + 2ax............... 1)
30² = v² + 2ax.............. 2)
(2) - (1) gives :
30² - v² = v² - 10²
900 + 100 = 2v²
1000 = 2v²
v² = 1000/2
v² = 500
v = √500
v = 10√5 m/s
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