A particle moving with a constant acceleration from A
to B in the straight line AB has velocities u and v at A
and B respectively. If C is the mid-point of AB then the
velocity of particle while passing C will be
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Answer:
Step-by-step explanationLet the distance between A and B=s and as mentioned C is the midpoint of A and B thus distance between A C and
C B=
2
s
From equation of motion we get distance between AB
v
2
=u
2
+2as
s=
2a
v
2
−u
2
----------(1)
Let speed of the vehicle be pm/s at point C
Again from equation of motion we get,
p
2
=u
2
+2a
2
s
as distance between A and C is
2
s
s=
a
p
2
−u
2
-------(2)
Computing 1 and 2 we get
a
p
2
−u
2
=
2a
v
2
−u
2
p
2
=
2
v
2
+u
2
p=
2
v
2
+u
2
:
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