Question

a particle moving with a uniform acceleration travels 24 m and 64 m in the first two consecutive intervals of 4 seconds each. its initial velocity is

Answer 1

I will assume that in first interval of 4s the distance covered is 24m and in next 4s it covers distance of 64 m.

Let a be uniform acceleration and u be initial velocity.

From equation of motion s=ut +(1/2)at^2, we have for first interval,

24=4u+8a or

6=u+2a……………….(1)

For next interval, initial velocity is u+4a. Therefore,

64=(u+4a)4+8a or

64=4u+24a or

16=u+6a……………..(2)

Solving equations (1) and (2),

u=1m/s.

Answer 2

Answer:

just by substituting the values we can find out the answer