Question

A particle moving with a velocity of 2m/s.After covering 63 m it velocity is observe to be 16m/s.Calculate it acceleration.​

Answer 1

Answer:

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Answer 2

Answer:

initial velocity = 2 m/s

final Velocity = 16 m/s

distance covered = 63 m

using 3rd equation of motion that is 2as = (v)² - (u)²

so ,

2 × a × 63 = (16)² - (2)²

126 × a = 256 - 4

126 × a = 252

a = 252/126

so a = 2 m/s²