Question

a particle moving with an initial velocity of 5.0 m/s is subjected to a uniform acceleration of -2. 5m/s2 find the displacement in the next 4.0s. ( URGENT PLEASE) ​

Answer 1

Explanation:

Initial velocity = 5 m/s

Acceleration = 2 m/s²

Time = 4 seconds

To calculate:

The displacement

Solution:

The displacement = 36 m

Using concept:

Second equation of motion

Using formula:

{\small{\underline{\boxed{\sf{\rightarrow s \: = ut \: + \dfrac{1}{2} \: at^2}}}}}

→s=ut+

2

1

at

2

Where, s denotes displacement or distance or height, u denotes initial velocity, t denotes time taken and a denotes acceleration.

Required solution:

\begin{gathered}:\implies \sf s \: = ut \: + \dfrac{1}{2} \: at^2 \\ \\ :\implies \sf s \: = 5(4) + \dfrac{1}{2} \times 2(4)^{2} \\ \\ :\implies \sf s \: = 20 + \dfrac{1}{2} \times 2(16) \\ \\ :\implies \sf s \: = 20 + \dfrac{1}{2} \times 32 \\ \\ :\implies \sf s \: = 20 + 1 \times 16 \\ \\ :\implies \sf s \: = 20 + 16 \\ \\ :\implies \sf s \: = 36 \: m \\ \\ :\implies \sf Displacement \: = 36 \: metres\end{gathered}

:⟹s=ut+

2

1

at

2

:⟹s=5(4)+

2

1

×2(4)

2

:⟹s=20+

2

1

×2(16)

:⟹s=20+

2

1

×32

:⟹s=20+1×16

:⟹s=20+16

:⟹s=36m

:⟹Displacement=36metres

Henceforth, the displacement is 36 metres in next 4 seconds!