Question

A particle moving with an
initial velocity of 5 m/s is
subjected to a uniform
acceleration of - 2.5 m/s^2.
Find the displacement of the
particle in the next 4 sec.​

Answer 1

$\huge{\underline{\tt{\red{Answer-}}}}$

Displacement =0

$\huge{\underline{\tt{\blue{Explanation-}}}}$

Given:

Initial velocity =u=5m/s

Acceleration=a=$-2.5m/s^2$

Time =t=4sec

Displacement =s =?

From Second equation of motion:

$S=ut+ \dfrac{1}{2 }at^2$

$=5\times4+\dfrac{1}{2}\times(-2.5)4\times4$

$=20-25\times \dfrac{16}{2}\times10$

=20-20

=0 m

Answer 2

GIVEN;. INTIAL VELOCITY ( U) = 5 M/S

UNIFORM DECELERATION. = -2.5 m/s ^ 2

TIME = 4 SECONDS

BY USING ,SECOND EQUATION OF MOTION ;

S = UT + 1/2 AT^2

S = 5 × 4 +. 1/2 × (-2.5)(4)^2

=. 20 +. (-40)

=. -20 m