Question

A particle moving with an initial velocity of 5 metre per second is subjected to a uniform acceleration of -2.5 metre per second square find the displacement in the next 4 second ​

Answer 1

Answer:

0 metres

Explanation:

Given :

• Initial velocity = u = 5 m/s

• Acceleration of the particle = a = - 2.5 m/s²

• Time taken = t = 4 seconds

To find :

• Displacement of the particle

Using the second equation of motion :

S=ut+½×at²

S=5×4+½×-2.5×16

S=20-8×2.5

S=20-20

S=0 metres

The Displacement of the particle is equal to 0 metres which means the particle will come back to the initial position

Answer 2

Answer :

Displacement in the next 4 seconds is ' 0 m/s '

$\rule{100}2$

It given that,

• u = 5 m/s
• a = - 2.5 m/s²
• t = 4 sec
• s = ?

By using second  kinematical equation :

• S = ut + 1/2 at²

we can find the displacement.

Substitute the given values. we get,

s = 5 × 4 + 1/2 ( - 2.5 ) ( 4 )²

⇒ s = 20 + ( - 2.5 ) × 8

⇒ s = 20 - 20

∴ s = 0.

Answer : Displacement covered by the particle is 0 m/s.

$\rule{200}2$