Question

a particle moving with an initial velocity of 5m/s is subjected to a uniform accelaration of 2.5m/s2. find the displacement in the next 4 second

Answer 1

initial velocity,u = 5m/s
acceleration,a = 2.5m/s²
t=4s

Apply the 2nd equation of motion,

s = ut+at²/2
s =5×4 + 2.5×4²/2
s = 20 + 20 = 40m
Hence the body displacement 40 m in the next 4 seconds.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Displacement=40\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about a particle which is moving in a straight line with velocity and uniform acceleration.We have to find the Displacement of particle after 4 sec.

$\green{\underline \bold{Given : }} \\ :\implies \text{Initial \: velocity(u) = 5 \: m/s }\\\\ :\implies \text{Acceleration(a) = 2.5 \: m }/{s}^{2} \\\\ :\implies \text{Time(t) = 4 \: sec} \\ \\ \red{\underline \bold{To \: Find :}} \\\\ :\implies \text{Displacement= ?}$

• According to given question :

$\bold{By \:Third \: equation \: of \: motion} \\\\ :\implies s = ut + \frac{1}{2} a {t}^{2} \\\\ :\implies s = 5 \times 4 + \frac{1}{2} \times 2.5 \times {4}^{2} \\\\ :\implies s = 20 + \frac{1}{2} \times 2.5 \times 16 \\ \\ :\implies s = 20 + 20 \\\\ \green{:\implies s = 40 \: m}$