A particle moving with an initial velocity of 5m/s is subjected to a uniform acceleration of 2.5m/s2 . Find the displacement in the next 4 sec?
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Answered by
4
There is a hidden equation that
s = vt - 1/2at^2
= 5 ( 4 ) - 1/2 × ( 2.5 ) ( 16 )
= 20 - 10
= 10 m.
Hope it helps!
s = vt - 1/2at^2
= 5 ( 4 ) - 1/2 × ( 2.5 ) ( 16 )
= 20 - 10
= 10 m.
Hope it helps!
Jhani:
pls mark it best if understood
its 20 - 20 that is 0m displacement
Answered by
2
Hello !
Initial velocity = u = 5 m/s
Acceleration = a = -2.5 m/s²
Time = t = 4 seconds
Displacement = s = ?
second equation of motion ,
s = ut+ 1/2 at²
=5*4 + 1/2*(-2.5)*4²
=20-20
= 0 m
Displacement = 0 m
Initial velocity = u = 5 m/s
Acceleration = a = -2.5 m/s²
Time = t = 4 seconds
Displacement = s = ?
second equation of motion ,
s = ut+ 1/2 at²
=5*4 + 1/2*(-2.5)*4²
=20-20
= 0 m
Displacement = 0 m
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