Physics, asked by wwwkamlakarp89, 1 year ago

A particle moving with an initial velocity of 5m/s is subjected to a uniform acceleration of -2.5m/s2. Find the displacement in the next 4 sec.

Answers

Answered by YadavShashi
5
HEY.......
HERE IS U R ANSWER
===================================
u = 5
t = 4
a = -2.5

s = ut + 1/2 at^2
= 5*4 + 1/2 (-2.5) 16
= 20 - 20
= 0
===================================
HOPE IT WILL HELP YOU A LOT....
THANKU.....
Answered by rohit301486
3

\blue{\bold{\underline{\underline{Answer:}}}}

\tt\green{\therefore{{Displacement=0\:m}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline \bold{Given :}}

\tt:\implies {Initial \: velocity(u) = 5 \: m/s }

\tt:\implies {Acceleration(a) =-2.5 \: m }/{s}^{2}

\tt:\implies {Time(t) = 4 \: sec}

\red{\underline \bold{To \: Find :}}

\bold{By \:Third \: equation \: of \: motion}

 \tt:\implies s = ut + \frac{1}{2} a {t}^{2}

\tt:\implies {Displacement= ?}

 \tt:\implies s = 5 \times 4 + \frac{1}{2} \times (-2.5) \times {4}^{2}

  • Given Question

 \tt:\implies s = 20 -\frac{1}{2} \times 2.5 \times 16

 \tt:\implies s = 20 -20

\green{ \tt:\implies s = 0 \: m}

Similar questions