Question

A particle moving with an initial velocity of 5m/s is subjected to a uniform acceleration of -2.5m/s². Find the displacement in the next 4 sec.

Answer 1

Answer:

Displacement in next 4 sec = 15 m

Explanation:

u = 5 m/s

a = -2.5 m/$s^{2}$

t = 4 sec

$s = ut + 0.5 at^{2}$

s = 5*4 - 0.5*2.5*4

s = 20 - 1.25*4

s = 20 - 5

s = 15 m

Answer 2

$\large \sf \underline\orange{Given:-}$

• Initial velocity (u) = 5m/s
• acceleration (a) = -2.5m/s²

$\large \sf \underline\green{To \: Find:-}$

• Displacement in next 4 seconds!= ?

$\large \sf \underline\purple{Explanation:-}$

Using 2nd equation of equation,

$\large\bf{S = ut + \frac{1}{2}at {}^{2}}$

Here

S = displacement

u = initial velocity

t = time taken

a = acceleration

Now put the Given values..

$\begin{array}{r r r} \end{array}\sf{S \: = 5 \times 4 + \frac{1}{2} \times 2.5 \times (4) {}^{2} } \\ \\ \rightarrow \: \sf{S = 20 + \frac{1}{2} \times 2.5 \times 4 \times 4} \\ \\ \rightarrow \sf{S = 20 + 2.5 \times 8} \\ \\ \rightarrow \sf{S = 20 + 20} \\ \\ \rightarrow \sf{S = 40m}\begin{array}{r r r} \end{array} \\ \\ \fbox \purple{✭ \: S(displacement) = 40m}$