Question

A particle moving with an initial velocity of 60 m/s is brought to a rest in a distance of 120m.Assuming the declaration calculate​

Answer 1

Answer:

u=60m/s

v=0m/s

S = 120m

therefore

u²-v² = 2aS

=> -60² = 240a

=> a = 3600/240

=> 15m/s²

hence the rate of deceleration is = 15m/s²

hope it helped :)