Question

A particle moving with constant acceleration form A to B in straight line AB has velocities 'u' and 'v' at A and B respectively .Find the velocity at C ,the mid point of AB.

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Answer 1

Answer:

Correct option is

A

2

v

2

+u

2

Let the distance between A and B=s and as mentioned C is the midpoint of A and B thus distance between A C and

C B=

2

s

From equation of motion we get distance between AB

v

2

=u

2

+2as

s=

2a

v

2

−u

2

----------(1)

Let speed of the vehicle be pm/s at point C

Again from equation of motion we get,

p

2

=u

2

+2a

2

s

as distance between A and C is

2

s

s=

a

p

2

−u

2

-------(2)

Computing 1 and 2 we get

a

p

2

−u

2

=

2a

v

2

−u

2

p

2

=

2

v

2

+u

2

p=

2

v

2

+u

2

Explanation:

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Answer 2

Answer:

hence the required answer is given