Question

A particle moving with initial velocity 4 m/s decelerate at constant rate of 2 m/s^ 2 . time after which its velocity become zero is​

Answer 1

Answer:

2 seconds

Explanation:

a= v-u /t

-2 = 0 - 4/t

t = 0-4/-2

t = 2

Answer 2

Given :  A particle moving with initial velocity 4 m/s decelerate at constant rate of 2 m/s^ 2

To Find :  time after which its velocity become zero

Solution:

particle moving with initial velocity 4 m/s

=> Initial Velocity u =  4 m/s

decelerate at constant rate of 2 m/s2

=> a = - 2 m/s²     ( negative sign shows deceleration )

Apply formula

V = u + at

V = Final Velocity

t = time

Velocity becomes zero hence V = 0

=> 0  = 4 - 2 * t

=> 2t = 4

=> t = 2

After 2 secs  velocity become zero

Learn More:

V=u+at u=2 a

https://brainly.in/question/13625067

in the diagram below the vectors U and V are at right angle to each ...

https://brainly.in/question/10126960