Question

A particle moving with SHM has an acceleration of 0.02m/s.when it's displacement is 0.08 m. Find its time period of oscillation

Answer 1

Answer:

Maximum acceleration

α=ω

2

y

∴0.5=ω

2

×0.02

or ω

2

=

0.02

0.5

=25

So, ω=5

Now, maximum velocity is

v=aω=0.1×5=0.5m/s

Explanation:

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