A particle moving with uniform acceleration along a straight line from rest. The percentage increase in displacement during sixth second compared to that in 5th second is
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The percentage increase in displacement during sixth second compared to that in 5th second is 44%
Explanation :
Let the acceleration of the particle is a m/s²
From the laws of motion we know that,
S = ut + at²/2
since u = 0, hence
S = at²/2
Displacement at the end of 5 second,
S₅ = a(5)²/2 = 12.5a
Displacement at the end of 6 second,
S₆ = a(6)²/2 = 18a
Increase in displacement,
S = 18a - 12.5a = 5.5a
Hence percentage increase in displacement
= (5.5/12.5) x 100
= 44%
Hence The percentage increase in displacement during sixth second compared to that in 5th second is 44%
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