Question

a particle moving with uniform acceleration along x axis at x1 = 10 and x2 = 20 at t = 6 and t = 10 respectively. If its velocity at t = 6 is 0.5 m/s it acceleration is

Please, its VERY URGENT!!!

Answer 1

Answer:

X1=10m at t=6sec at v= .50 m/s

X2=20m at t=10sec

So,

S=10m

t= 4 sec

u= .50 m/s

S=ut+1/2at2

10=1/2*4+1/2*a*4*4

10=2+8a

a=1 m/s2

Answer 2

the acceleration of the particle along the x axis is 2.5 m/s^2.

Given:

The particle is moving with uniform acceleration along x axis

The position of the particle at t = 6 and t = 10 is x1 = 10 m and x2 = 20 m, respectively.

The velocity of the particle at t = 6 is 0.5 m/s

To find: Acceleration of the particle along x axis

Solution:

• Calculate the velocity of the particle at t = 10:
• Use the equation of motion v = u + at, where v is the final velocity, u is the initial velocity (0.5 m/s), a is the acceleration and t is the time (4 s).
• v = u + a * t
• v = 0.5 + a * 4

• Calculate the displacement of the particle from x1 to x2:
• Use the equation x = x1 + vt + (1/2)at^2, where x is the displacement, x1 is the initial position (10 m), v is the final velocity (calculated in step 1), a is the acceleration and t is the time (4 s).
• x = x1 + vt + (1/2)at^2
• x = 10 + (0.5 + a * 4) * 4 + (1/2) * a * 4^2
• Solve for acceleration (a):
• Use the equation a = 2(x2 - x1 - u * t) / t^2, where x2 is the final position (20 m), x1 is the initial position (10 m), u is the initial velocity (0.5 m/s), t is the time (4 s) and a is the acceleration.
• a = 2(x2 - x1 - u * t) / t^2
• a = 2(20 - 10 - 0.5 * 4) / 4^2

• Substitute the values in the equation:
• Replace the calculated values of u, t, x1, x2 and v in the equation obtained in step 3 to get the acceleration.

The acceleration of the particle along the x axis can be calculated using the equations of motion.

Given the initial velocity of the particle at t = 6 as 0.5 m/s, the final velocity at t = 10 as v, the initial position of the particle at t = 6 as x1 = 10 m, the final position at t = 10 as x2 = 20 m, and the time as t = 4 s, the acceleration can be calculated as follows:

a = 2(x2 - x1 - u * t) / t^2

= 2(20 - 10 - 0.5 * 4) / 4^2

= 2.5 m/s^2

Thus, the acceleration of the particle along the x axis is 2.5 m/s^2.

To learn more about acceleration from the given link.

https://brainly.in/question/789316

#SPJ3