A particle moving with uniform acceleration along x -axis is at x1=10m and x2=20m at t=6s and t=10s respectively.If its velocity att =6s is 0.5ms^(-1) its acceleration is
Answers
Answered by
2
Explanation:
❀ʀᴇǫᴜɪʀᴇᴅ ᴀɴsᴡᴇʀ
❀ Solution :-
➥ s
n
distance travelled in n sec-distance travelled in (n-1) sec
s
n
=(u
1
n+
2
1
an
2
)−(u
1
(n−1)+
2
1
a(n−1)
2
)
=u
1
+
2
1
a(n
2
−(n−1)
2
)
=u
1
+
2
a
(+2n−1)
=u
1
+an−
2
a
Comparing with: s
n
=0.4n+9.8
a=0.4,u
1
−
2
0.4
=9.8
u
1
−
2
0.4
=9.8
u
1
=10 m/s
Answered by
4
Acceleration is 10 metre per second
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