Question

A particle moving with uniform acceleration covers a distance 5m in 7th second and 8m in 12th second during its motion find velocity of the particle at the end of 11th second and also find total distance travelled by the body in 15 seconds

Answer 1

Use the eqn.

Snth = u + a/2 × (2n-1)

Put the value of 'snth' and 'n'

as it is given to u

U will get two equations

10 = 2u + 13a......(I)

16 = 2u +23a......(ii)

6/10 = a

a=3/5

Now find the value of u similarly

Use the similar eqn above written

To find for 11 to sec. Just put n= 11

U will get to know the value of snth

To find the value of dis. In 15 sec

Use the eqn s = ut + 1/2 at²

And find the value of S