A particle moving with uniform acceleration from A to B along a straight line has velocities 10 m/s and 20 m/s at point A and B respectively. If C is the mid-point of A and B, then velocity of the particle at point C is
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Here you have not mentioned anything about acceleration . so i making this question by assuming that acceleration is uniform.
let u be the velocity at B.
Since B is the mid point of AC.
so, AB = BC = s
so ,
on applying the formula v^2- u^2 = 2as
for AC
u^2- 7^2= 2as - (1)
u^2–49= 2as
similarly for BC
289 - u^2=2as -(2)
from equation 1 and 2, we get
u^2–49=289- u^2
on solving we get
u= 13 m/s
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