A particle moving with uniform acceleration from A to B along a straight line has velocities V1 and V2 at A and B respectively if c is the midpoint between A and B then determine the velocity of the particle at c
plz help me guyz
Answers
Answered by
19
I think this is likely to be....
sq (v2)-sq (v1)=2as. ....
from this
s=sq (v2)-sq(v1)/2a
so s/2=sq (v2)-sq (v1)/4a. .........divide both sides for middle distance.... (1)
now distance=speed×time
(1)= v×time. ..... (2)
now find t from v=u+at...
nd put in eq 2
then v= (v2+v1)/4
sq (v2)-sq (v1)=2as. ....
from this
s=sq (v2)-sq(v1)/2a
so s/2=sq (v2)-sq (v1)/4a. .........divide both sides for middle distance.... (1)
now distance=speed×time
(1)= v×time. ..... (2)
now find t from v=u+at...
nd put in eq 2
then v= (v2+v1)/4
supercool3:
thanks skkkk
Answered by
16
Since we (v2²-v1²)/2a=d here d is the distance covered
At point c le velocity be x then,
(X²-v1²)/2a=d/2 since its the midpoint
(X²-V1²)/a=(v2²-v1²)/2a
2X²=v2²-V1²+v2²
2x²=V2²+V1²
Hence , x=(v2²+v1²)/2
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