Question

A particle moving with uniform acceleration has average
velocities V1 V2 and V3 over the successive intervals of
time t1 t2 and t3 respectively. The value of (v1-v2)/(v2-v3) will be ​

Answer 1

Explanation:

Assume the particles moves the separation AB, BC and CD in time t1,t2 and t3 individually.

Speed at B = u+at1

Speed at C = u+a(t1+t2)

Speed at D = u + a( t1+t2+t3)

Normal speed (v1)=( starting +final)/2

= (u + u + at1)/2

= u+1/2 at1

V2 = u+at1+1/2at2

V3 = u+ at1+at2+1/2at3

There fore we get

(V1-V2)/(V2-V3) = (t1+t2)/(t2+t3)

Hence proved.

I hope you understand it....