Question

A particle moving with uniform acceleration in a straight line has a speed of v ms–1, at position'x' meters is given by v=√(180-16x), the acceleration is

Answer 1

Answer:

We know

$a = v. \frac{dv}{dx} \\ \\ a = \sqrt{180 - 16x} . \frac{d}{dx} ( \sqrt{180 - 16x} ) \\ \\ a = \sqrt{180 - 16x}. \frac{ - 16}{2\sqrt{180 - 16x}} \\ \\ a = - 8 \: m {s}^{ - 2}$