Question

a particle moving with uniform accerlation along x axis crosses x=10 m and x=50m with velocity 10m/s and 30m/s respectively.the velocity with which it crosses the point x=40m is​

Answer 1

Answer:

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Answer 2

Given:

A particle moving with uniform accerlation along x axis crosses x=10 m and x=50m with velocity 10m/s and 30m/s respectively.

To find:

The velocity with which it crosses the point x=40m ?

Calculation:

Let the acceleration of the object be "a".

So, in between the position x = 10m and x = 50m, we can say that:

$\therefore \: {v}^{2} = {u}^{2} + 2as$

$= > \: {(30)}^{2} = {(10)}^{2} + 2a(50 - 10)$

$= > \: {(30)}^{2} = {(10)}^{2} + 2a(40)$

$= > \: 900 = 100 + 2a(40)$

$= > \: 2a(40) = 800$

$= > \: 80a = 800$

$= > \: a = 10 \: m {s}^{ - 2}$

Now , in between x = 10m and x = 40 m, we can say that:

$\therefore \: {v}^{2} = {u}^{2} + 2as$

$= > \: {v}^{2} = {(10)}^{2} + 2(10)(40 - 10)$

$= > \: {v}^{2} = {(10)}^{2} + 2(10)(30)$

$= > \: {v}^{2} = {(10)}^{2} + 600$

$= > \: {v}^{2} = 100 + 600$

$= > \: {v}^{2} = 700$

$= > \: v = \sqrt{700}$

$= > \: v = 26.45 \: m {s}^{ - 2}$

So, velocity at x = 40 m is 26.45 m/s².

Hope It Helps.