Question

a particle moving with uniform speed v changes its direction by angle theta in time t. find the magnitude of average acceleration during this time??​

Answer 1

Answer:

Since, magnitude of velocity, i.e speed, is constant, thus no change in magnitude of velocity.

But, magnitude of change in velocity is given as:

∣

v

f

−

v

i

∣=

v

2

+v

2

−2.v.v.cosθ

=v

2(1−cosθ)

Now, 1−cos2θ=2sin

2

θ,or1−cosθ=2sin

2

θ/2

Thus, magnitude of change in velocity =v

4sin

2

θ/2

=2v.sin(θ/2)

Explanation:

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