A particle moving with velocity 3+6t+9t cm/s find the displacement of particle in interval of 5sec to 8sec
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Velocity of the particle v=(3+6t+9t
2
) cm/s
∴ Acceleration of the particle a=
dt
dv
=6+18t cm/s
2
Acceleration at t=3 s, a
t=3
=6+18(3)=60 cm/s
2
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