Question

A particle moving with velocity 5 m per sec accelerates uniformly with acceleration of 2 m per sec2 for 10 sec . The displacement in last one sec is​

Answer 1

☯ SOLUTION :

Given :

◾ Initial velocity of particle = 5mps

◾ Acceleration of body = 2m/s^2

◾ Time interval = 10s

To Find :

◾ Displacement in last second.

Formula :

✏ Formula of displacement covered in last second is given by

✍️ d = u + a/2(2n-1)

• d denotes displacement in nth second
• u denotes initial velocity
• a denotes acceleration
• n denotes no. of second

Calculation :

→ d = u + a/2(2n-1)

→ d = 5 + 2/2(2×10-1)

→ d = 5 + 1(20-1)

→ d = 5 + 19

→ d = 24m