Question

A particle of 10 kg is moving in a constant acceleration 2m/s starting from rest.
What is its momentum and velocity after time (a) t=1sec (b) t2sec​

Answer 1

$\huge{\underline{\tt{\red{Answer-}}}}$

Mass = 10kg

Initial Velocity(u) = 0m/s

Final Velocity(v) = ?

Acceleration(a) = 2m$s^2$

We know that,

v = u + at

a)t=2 sec

$v = 0 + (2m/s^{2} \times 2s)$

v = 0 +  ( 4m/s)

v = 4m/s

Now let's find Momentum(p)/

Momentum (p) = Mass(m) x Velocity (v)

Momentum (p) = 10kg x 4m/s

Momentum (p) = 40kg m/s

b)t=1 sec

$v = 0 + (2m/s^{2} \times 1s)$

v= 2m/s

Now let's find Momentum(p)/

Momentum (p) = Mass(m) x Velocity (v)

Momentum (p) = 10kg x m/s

Momentum (p) = 20kg m/s

Answer 2

Answer:

Acceleration is the rate of change of velocity with respect to time.

Acceleration = velocity / time

(1) = At t = 1 sec velocity and momentum will be:

2 = v / 1

vel = 2 m/s

Momentum (p) is the product of mass and velocity

P = mv

P = 20 kg*m/s

(2) = at t = 2 sec

Acc = v / t

2 = v / 2

v = 4 m/s

Momentum = m × v

Momentum = 40 kg*m/s

Thanks!