A particle of 10 kg is moving in a constant acceleration 2m/s2 starting from rest. What is its momentum and velocity if time is equal to 2 seconds.
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Given:-
- Initial velocity ,u =0m/s
- Acceleration, a = 2m/s²
- Time taken ,t = 2 s
- Mass ,m = 10kg
To Find:-
- Final velocity ,v
- Momentum, ∆P
Solution:-
Firstly we calculate the Final velocity of the particle . So by using 1st equation of motion
• v = u+at
Substitute the value we get
→ v = 0 + 2×2
→ v = 4m/s
Therefore, the Final velocity Of the particle is 4m/s
Now , we calculate the Momentum of the particles.
As we know that moment is the product of mass and velocity .
• ∆P = mv
Substitute the value we get
→ ∆P = 10×4
→ ∆P = 40 Kgm/s.
Therefore the moment of the particles is 40kgm/s.
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m = 10 kg
a = 2m/s ^2
t = 2 sec
u = 0 m/s (Starting from rest)
v = 4 m/s
Also , momentum = m X v
= 10 X 4
= 40 kg m/s
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