Math, asked by machavarapukrupasamp, 1 month ago

A particle of 10grams is moving with a velocity 2j+j+3k(cm/s) magnitude of its linear momentum is

Answers

Answered by Anonymous

0

Answer:

|P|=10√14

Step-by-step explanation:

P= mv= 10(2i+j+3k)= 20i+10j+30k

|P|=√20²+10²+30²

|P|=√400+100+900

|P|=√1400

|P|=√14*100

|P|=10√14

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