A particle of charge 0.4c is projected with speed 2×10^4 m/s into a uniform magnetic field of strength 0.5t. if the particle's velocity as it enters the field is perpendicular to "B". What is the magnitude of the magnetic force on this particle
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Answer:
F = 4000N
Explanation:
F = qvB sin@
@ = 90° ; sin90° = 1
F = 0.4 × 2 ×10^4 × 0.5
F = 4000N
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