A particle of charge 2×10 is to -4is taken from a point at a potential of 40 v to another point at potential of 240v calculate the work done
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Answer:
4 × 10^(-2) J
Explanation:
Q = 2 × 10^(-4) C
V1 = 40 V
V2 = 240 V
V2 - V1 = W/Q
240 V - 40 V = W/2 × 10^(-4) C
200 V = W/2 × 10^(-4) C
W = 200 V × 2 × 10^(-4) C
W = 400 V × 10^(-4) C
W = 4 × 10^(-2) J
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