Physics, asked by abinasha594, 6 months ago

A particle of charge 3 x 10^-19 C is situated in a
uniform electric field directed to the left. In moving to
the right a distance of 0.05 m, the work of an applied
force is 6 x 10^-5 J and the change in kinetic energy is
4.5 x 10^-5 J. Find the magnitude of electric intensity.​

Answers

Answered by meenaj7067
0

Answer:

I think you should search on Google.

surely you will get your answer.

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