Physics, asked by ishakhan3556, 1 year ago

A particle of charge 'q' and mass 'm' moving with a velocity 'v' enters perpendicularly in a uniform magnetic field 'B' describes a circular path.What will be the radius of that path?
A)mv\Bq
B)mqv\B
C)mvB\q
D)mqB\v

Answers

Answered by Ahmedteach

2

Answer:A mv/qb

Explanation:

mv2/r=qvb

r=mv/qb

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