A particle of charge q and mass m with velocity v(i+j)
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A particle of charge q and mass M is moving with velocity V
A particle of charge q and mass m is moving with velocity v. ... A charge q projected perpendicular to the uniform magnetic field B with velocity v. The perpendicular force, F = q(v X B), acts like a centripetal force perpendicular to the magnetic field. Then, the path followed by charge is circular as shown in the figure.
Answer:
A particle of charge q and mass m is moving with velocity v. It is subjected to a uniform magnetic field B directed perpendicular to its velocity. Show that, it describes a circular path. Write the expression for its radius. Foreign 2012 Sol. A charge q projected perpendicular to the uniform magnetic field B with velocity v. The perpendicular force, F = q(v X B), acts like a centripetal force perpendicular to the magnetic field. Then, the path followed by charge is circular as shown in the figure.
