A particle of m = 5 kg is momentarily at rest at x = 0 at t = 0. It is acted upon by two forces F1 and F2. F1 =70j .The direction and magnitude of F2 is unknown. The particle experiences a constant acceleration a in direction as shown, Neglect gravity.
find F2
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F2=F1 Divide By Mass of the particles
therefore answer is 14 meter per second square
therefore answer is 14 meter per second square
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Answer:37.5 Newton along
Explanation:component splitting
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