A particle of mass 0.01kg travels along a space curve with velocity given by 4i^+16k^ m/s. After some time it's velocity becomes 8i^+20k^ m/s due to the action of a conservative force. Find the work done on the particle during this interval of time?
Answers
Answered by
80
KE initial = 1/2 * 0.01 * [4^2 + 16^2] Joules
KE final = 1/2 * 0.01 * [8^2 + 20^2 ] J
Work done = 1/2 * 0.01 * [64 + 400 - 16 -256 ]
= 0.96 J
KE final = 1/2 * 0.01 * [8^2 + 20^2 ] J
Work done = 1/2 * 0.01 * [64 + 400 - 16 -256 ]
= 0.96 J
Similar questions