Question

A particle of mass 0.2 kg executes simple
harmonic motion with amplitude of 0.1 m
and a timeperiod of 1/2 seconds. The
restoring force acting on the particle when
its displacement is 0.08 m is
(A) 0.128 N
(B) 0.16 N.
(C) 0.256 N.
(D) 1.28 N.​

Answer 1

Answer:

0.256 N. this is your answer okay bro