A particle of mass 0.3 kg is subjected to a force F = -kx with k = 15 Nm. What will be its initial
acceleration if it is released from a point 20 cm away from the origin
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Answer:
10 m/sec^2 towards the origin
Explanation:
F= -kx
Given, k= 15 N/m
x= 20 cm=0.20 m
So, F= -15*0.20= -3.0 N
Again, F= ma
given, m= 0.3 kg
So, Acceleration, a= F/m= -3.0/0.3 m/sec^2= -10 m/sec^2 (negative sign shows acceleration towards the origin.
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