A particle of mass 0.3 kg is subjected to a force of ap is equal to minus kx with k is equal to 15 mm what will be its initial acceleration if it is released from a point 20 cm away from the origin
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mass of the particle, m = 0.3 kg
k = 15 N/m
x = 20 cm = 0.2 m
Let the acceleration of the particle = a
Using the Newton’s 2nd law of motion we get,
F = m* a or, -kx = ma
or, - 15 * 0.2 = 0.3 * a or, a = -3.0/0.3
or, a = -10m/s^2
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so the answer is 10 m sec square
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