A particle of mass 0.3 kg is subjected to force f is equals to K X with K is equals to 15 Newton per metre and X being its distance from the origin what will be its initial acceleration if it released from a point 20 CM away from the origin
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YOU have to balance the force in order to get an acceleration
KX = Ma
15*0.20 = 0.3*a
3 = 0.3a
10 = a
Thus acceleration will be 10m/sec^2
KX = Ma
15*0.20 = 0.3*a
3 = 0.3a
10 = a
Thus acceleration will be 10m/sec^2
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