Question

A particle of mass 0.5 kg is displaced from position
Fi (2,3, 1) to , (4,3,2) by applying a force of magnitude
30 N which is acting along (i+j+k). The work done by
the force is
(b) 30/3J
(a) 10/30
(c) 30 J
(d) none of these​

Answer 1

Answer:

W = f vector dot d vector

W = 30/root 3* (i+j+k). (2i+k)=10root3*(2+1)=30root3 joule

Option a